In order to keep the ZPM replications threads clean I've created this thread when questions can be asked and discussion related to ZPM's functionality can continue.
We can discuss here about the standing waves on ZPM's output, the waves propagation in the core and any subjects not directly related to those ZPM replications.
Regards,
Fighter
| "If you want to find the secrets of the universe, think in terms of energy, frequency and vibration." | ||
| Nikola Tesla | ||
In order to keep the ZPM replications threads clean I've created this thread when questions can be asked and discussion related to ZPM's functionality can continue.
We can discuss here about the standing waves on ZPM's output, the waves propagation in the core and any subjects not directly related to those ZPM replications.
Regards,
Fighter
| "If you want to find the secrets of the universe, think in terms of energy, frequency and vibration." | ||
| Nikola Tesla | ||
Quoting:bigmotherwhale
Thanks Jagau, if this is not an LC phenomenon, then you have a propagation speed of around 8000 m/s in your core with a 32cm magnetic path, please correct me if im wrong maths isnt my strong point.
could you try altering the capacity of one of the coils with a capacitor and measuring again or try pumping the core at this freqency?
Hey bigmotherwhale,
I am curious how did you calculated the propagation speed to be 8000m/s and also the magnetic path of the core to be 32cm by simply knowing the frequency? I want to do some experiments and I need that information.
Thank you.
Quoting:Jagau
My replication of Figther's ZPM. As my two coils were already mounted on an AMCC320 I was able to replicate quickly.
In the first image the 2 coils mounted on the AMCC320
In the second image when the power supply is turned on at 24 volts DC he sees an input power of 4.32 watts on 24 volts and 180 ma when my TL494 oscillator is supplied to both coils through an IGBT pulsed at 38.2% on the high side. Channel1 is IGBT pulse
Image of the oscilloscope with the current probe on the PS
You can notice that the oscilloscope show on a my TEK current probe (green) 292mv =292 ma (rectangular form) and 38.2% DTC
Last image the 118 volt 4 Watts lamp lit with 34 ma x118.8v = therefore 4.0392 watts of power produce at the output on a large capacitor and 4 diodes in parallel in order to produce an almost pure DC which can be read by the 2 DDMs
Calculation of input power in DCM mode with reactive component.
As indicated by the power supply we have an instantaneous pulse power of 4.32 watts, this is the instantaneous power not the average power over time.
V and I is what PS provided a DM as wrong lecture for input due to high frequency so to calc PIn we take well known formula for inductor.
Irms on scope is 0.292 Amp, DC voltage is 24volts
Pin= I*V*sqrt(Duty_Cycle)/sqrt(3)
Pin= 0.292 Amp x 24 Vdc x sqrt 0.382 / sqrt 3 = 2.533 wattsSo for Pout of 4.032 watts i need only 2.533 watts at input, Still a pretty good COP
Jagau
Hey Jagau,
I followed your thread recently to understand your setup but I am confused of some things. Maybe you can clear them up or someone else. Lets look at the oscilloscope shot. The green waveform is the current of the PS and the yellow is what? the voltage waveform of the PS? I am asking this because your PS display is showing 24V but the scope is showing 8.96 Peak to Peak so at 38.2 Duty Cycle, the RMS voltage should be even lower than that. I think you understand my confusion, so again, what is the yellow waveform showing?
Thank you.
Hi
This is only the pulse at the gate of IGBT coming from TL494 at 1044 hertz by square wave oscillator. The oscillator is powered by a 12 volt DC battery and you can see the linear rise of current in the green triangle shape, when the pulse is present. I hope that takes away your confusion.
Jagau
What we consider to be empty space is merely a manifestation of unawakened matter. N.T.
Quoting:Jagau
Hi
This is only the pulse at the gate of IGBT coming from TL494 at 1044 hertz by square wave oscillator. The oscillator is powered by a 12 volt DC battery and you can see the linear rise of current in the green triangle shape, when the pulse is present. I hope that takes away your confusion.
Jagau
So only the green waveform is measuring the current from the PS. That green sawtooth waveform is pretty interesting especially at that low frequency. It shows that the maximum current in the circuit hasn't been reached else we would've seen a horinzontal line after some time of rise. That shows you have a high inductance in those coils.
In fact Vasile, if you look at the circuit provide by Fighter,
these are two coils in phase opposition that are pulsed which produces a parametric resonance between these two coils. In my case, measured in phase opposition, I have a measured with an inductance meter 74 uh (microhenries) for total of the two coils in my case.
As for the maximum current, it is determined by the duty cycle, the curve obtained is characteristic of this type of pulsed circuit. If you go over a certain limit, the fuses will burn.
Wikipedia shows a nice picture that represents the characteristics of a similar circuit well, you can see the same voltage characteristics versus current waveforms at on and off. Same i get for current in red triangle
Try this: As I drew on the diagram, If you place a capacitor of 1uf not polarized in parallel with the lamp you will have a better luminosity of the lamp.
Jagau
What we consider to be empty space is merely a manifestation of unawakened matter. N.T.
Thanks Jagau, if this is not an LC phenomenon, then you have a propagation speed of around 8000 m/s in your core with a 32cm magnetic path, please correct me if im wrong maths isnt my strong point.
could you try altering the capacity of one of the coils with a capacitor and measuring again or try pumping the core at this freqency?
I quoted bigmotherwhale in a few posts earlier about how he managed to deduce the speed of propagation thru the core to be 8000m/s and also the magnetic path of the core to be 32 cm, by only knowing the frequency, but he hasn't responded yet and I wanted to ask also the same question to everyone else on the forum maybe someone knows the answer. So, anybody know?
bigmotherwhale was last online on 13th January, you may try asking him through personal message here.
He will receive a notification on email about your message.
Regards,
Fighter
| "If you want to find the secrets of the universe, think in terms of energy, frequency and vibration." | ||
| Nikola Tesla | ||
Your question:
I quoted bigmotherwhale in a few posts earlier about how he managed to deduce the speed of propagation thru the core to be 8000m/s and also the magnetic path of the core to be 32 cm, by only knowing the frequency, but he hasn't responded yet and I wanted to ask also the same question
I already asked him myself this question on dec 12
Jagau posted this 12 December 2022
Can you be more specific so I can understand better?
What is your calculation that you used in the moment for the wave return?Jagau
and he answered dec 12
bigmotherwhale posted this 12 December 2022
The period (time) of the cycle and the lenght of the magnetic pathway.
Propagation delay is equal to d / s where d is the distance and s is the wave propagation speed.
here you have the answer to your question.
Jagau
What we consider to be empty space is merely a manifestation of unawakened matter. N.T.
Quoting:Fighter
He will receive a notification on email about your message.
Thanks for the advice, I did that just now.
Quoting:Jagau
bigmotherwhale posted this 12 December 2022
The period (time) of the cycle and the lenght of the magnetic pathway.
Propagation delay is equal to d / s where d is the distance and s is the wave propagation speed.
here you have the answer to your question.
Jagau
So he had the frequency which was 39.68KHz.
He could deduce the period (time) of the cycle which is 1 second over 39680 = 0,000025 s = 25us
But what about the rest? like the "lenght of the magnetic pathway" or the 2 variables from the propagation delay formula (d/s), the distance and the wave propagation speed? How did he calculated those?
No one online at the moment
