YoElMiCrO's Ferro-Magnetic Resonance

Hi everyone.

As I commented earlier, with the circuit I made I could
perform innumerable physical tests that were corroborating the hypotheses
varied that arose on the actual operation of the circuit with two TL494 from Akula.
After doing a lot of analysis this is the best approach.
I will try to explain its operation as simple as possible!
The circuit in question is that of the two TL494s, I think flashlight # 3.

It has a TL494 in free osc mode, frequency and duty cycle are controlled.
the duty controlled from pin 4 which controls the dead-time when configured
in push-pull mode, pin13 to Vref.
It is configured in common mode, since pin 13 at ground potential.
In this way we can control the duty 0 ~ 100%.
This free oscillator is key in its operation, but now we will see it.
The following TL494 is a Boost-Converter whose duty does not exceed 50%,
This is in charge of keeping its operation stable through the control loop,
which modifies the duty inversely proportional to the output voltage.

This is my point of view on the concept of operation.
This circuit involves two concepts, one that is already known and the other still under study.
The first one tries to have the least loss, (better efficiency) and it goes away that
reaching a maximum BH/2 magnetic energy is better to increase it cycle by cycle.
The second is about the negative region of ur.

It happens as follows ...
The free oscillator circuit causes increments of 100Gaus for example.
Your duty in question will be such that EdcTon = VfbToff and the stored energy
BH/2 will return to the input capacitor, this way the source will only have to
provide the energy of losses of the circuit and its consumption will be very low.
Now the Boost-Converter is participating.
It has a lower frequency such that its maximum duty (also controlled
from pin 4) fit the number of free oscillator pulses needed that
increase the energy discreetly until B is such that its ur is maximum.
As the two coils have the same phase, during the time that it is active
the primary with the highest number of turns (the Boost-Conveter), the one with the fewest turns will see a short
during the toff cycle and will not be able to release stored energy BH/2
because EdcTon is now unequal to VfbToff.
This causes the current to increase cycle by cycle, just as the Boost-Converter applies
Toff the short seen by the free oscillator is no longer, this causes all the
stored energy release, but remember that this oscillator is free.
During this Boost Toff time the tension in the free osc mosfet drain
it will be higher than Edc and its next cycles over saturate the core making it pass
by the negative slope of ur, in this way during the Toff time of this oscillator
free the flyback voltage peak (Vfb) in the drain will be of various magnitudes (So
protection in the mosfet drain) while the energy stored in the area lasts
left of the hysteresis (Br/Bs) until it is completely delivered to the
Input Load/Capacitor.
It is this energy that added to the stored BH/2 causes the AU.
Now we have an energy that comes from the ferrite itself + the one that we previously stored
cycle by cycle.
This explains the reason for a gap in the ferrite.

I will make a final circuit with discrete ICs and when it is 100% functional
I'll post it so all can replicate it.

I hope serve something.
Thank you in advance.

YoElMiCrO.